Switch-case, simple calculator . . .

11.     Write a program to perform some mathematic functions with the help of “switch-case” statement.

#include<stdio.h>

#include<conio.h>

void main()

{

int a,b,ans;

char c;

clrscr();

printf("\ Enter a and b:");

scanf("%d%d",&a,&b);

printf("\n Enter operator:");

fflush(stdin);

scanf("%c",&c);

switch(c)

{

case'+':ans=a+b;

      break;

case'-':ans=a-b;

      break;

case'*':ans=a*b;

      break;

case'/':ans=a/b;

      break;

}

printf("\n ans %d",ans);

getch();

}

12.     Print the Fibonacci series

#include<stdio.h>

#include<conio.h>

void main()

{

int a=1,b=1,s=3,c,ch;

clrscr();

printf("how many steps=");

scanf("%d",&ch);

printf("%5d%5d",a,b);

for(s=3;s<=ch;s++)

{

      c=a+b;

      printf("%5d",c);

      a=b;

      b=c;

}

getch();

}

13.      Write a program to check whether the number entered by the user is Palindrome or not.

#include<stdio.h>

#include<conio.h>

void main()

{

int x=0,y,no,temp;

clrscr();

printf("no");

scanf("%d",&no);

temp=no;

while(no>0)

{

y=no%10;

x=(x*10)+y;

no=no/10;

}

if(temp==x)

      printf("palindrome");

      else

      printf("not");

getch();

}

14.     Make the simple calculator, where the operator to perform mathematical task will be entered by the user.

#include<stdio.h>

#include<conio.h>

void main()

{

int a,b,c;

char d;

clrscr();

printf(" Enter any two no=");

scanf("%d%d",&a,&b);

printf("enter operator");

scanf("%c",&d);

switch(d)

{

case '+': c=a+b;

      printf("%d",c);

      break;

case '-':c=a-b;

      printf("%d",c);

      break;

case '*' :  c=a*b;

      printf("%d",c);

      break;

default:

      printf("invalid");

}

getch();

}

15.     Simple example using “continue” keyword.

#include<stdio.h>

#include<conio.h>

void main()

{

int no;

clrscr();

printf("enter any no=");

scanf("%d",&no);

for(no=1;no<=100;no++)

{

      if(no%13==0)

      continue;

      printf("%5d",no);

}

getch();

}

Made By: Chaudhary Amit V.